case "${Column}" when "EXECUTION" then [LONG_EXECUTION] when "EXEVOLUME" then [VOLUME] when "COUNT" then [LONG_COUNT] end as [${Column}]
Mar 12, 2014
Feb 19, 2014
Differrence between tow rows in spotfire
sum([TUP]) OVER ([Row]) - sum([TUP]) OVER (previous([Row]))
Dec 17, 2012
Remove virus from Pendrive
1) முதலில் பென்டிரைவை உங்கள் கணினியில் சொருகி கொள்ளுங்கள்.
2) Start ==> Run ==> CMD==> Enter கொடுக்கவும்.
3) இப்பொழுது பென்ட்ரைவ் எந்த ட்ரைவில் உள்ளது என பாருங்கள். My Computer செல்வதன் மூலம் கண்டறியலாம்.
4) உதாரணமாக E: டிரைவில் பென்ட்ரைவ் இருக்கிறது எனவைத்து கொள்வோம் அதற்கு நீங்கள் E: என கொடுத்து Enter அழுத்தவும்.
5) attrib -h -s -r /s /d *.*என டைப் செய்யுங்கள் ஒவ்வொருபகுதிக்கும் Space சரியாககொடுக்கவும்.
2) Start ==> Run ==> CMD==> Enter கொடுக்கவும்.
3) இப்பொழுது பென்ட்ரைவ் எந்த ட்ரைவில் உள்ளது என பாருங்கள். My Computer செல்வதன் மூலம் கண்டறியலாம்.
4) உதாரணமாக E: டிரைவில் பென்ட்ரைவ் இருக்கிறது எனவைத்து கொள்வோம் அதற்கு நீங்கள் E: என கொடுத்து Enter அழுத்தவும்.
5) attrib -h -s -r /s /d *.*என டைப் செய்யுங்கள் ஒவ்வொருபகுதிக்கும் Space சரியாககொடுக்கவும்.
Jul 20, 2012
Difference between Cell- level Encryption and Transparent Data Encryption
Difference between Cell- level Encryption and Transparent Data Encryption (TDE)
Cell- level Encryption
|
Transparent Data Encryption (TDE)
|
Granular control over which data is encrypted
|
Encrypts the
entire database
|
User‐aware encryption can control access on a need‐to‐know basis
|
Encryption is not user‐aware; data is open to all users who have
permission to access the database
|
Requires analysis to find sensitive data
|
No analysis required because entire database is encrypted
|
Affect table structure because encrypted data can only be stored
in varbinary data type columns.
|
No change is
required in table structure.
|
Database applications need to be modified to use specific
functions to encrypt and decrypt data.
|
No database application change needed.
|
Indexes, primary keys, and foreign keys cannot be encrypted.
|
No impact on indexing, primary keys, or foreign keys
|
Potential
impact on performance because indexes on encrypted columns are not used while
searching a value.
|
Small impact
on performance (up to 5%)
|
Jul 6, 2012
SQL Table Partition.
IF EXISTS (
SELECT name
FROM sys.databases
WHERE name = N'TestPartition')
DROP DATABASE TestPartition;
GO
CREATE DATABASE TestPartition
ON PRIMARY
(NAME='TestPartition_Part1', FILENAME= 'D:\Partition test\primary\TestPartitionPrimary.mdf', SIZE=2, MAXSIZE=100, FILEGROWTH=1 ),
FILEGROUP TestPartition_Part2
(NAME = 'TestPartition_Part2', FILENAME = 'D:\Partition test\Secondary\TestPartitionSecondary.ndf', SIZE = 2, MAXSIZE=100, FILEGROWTH=1 );
GO
use TestPartition
go
--DROP TABLE TestTable
GO
DROP PARTITION SCHEME TestPartition_PartitionScheme
GO
DROP PARTITION FUNCTION TestPartition_PartitionRange
GO
CREATE PARTITION FUNCTION TestPartition_PartitionRange (INT)
AS RANGE LEFT FOR
VALUES (10);
GO
CREATE PARTITION SCHEME TestPartition_PartitionScheme
AS PARTITION TestPartition_PartitionRange
TO ([PRIMARY], TestPartition_Part2);
GO
-- drop table TestTable
CREATE TABLE TestTable
(ID INT NOT NULL,
Date DATETIME)
ON TestPartition_PartitionScheme (ID);
GO
CREATE UNIQUE CLUSTERED INDEX IX_TestTable
ON TestTable(ID)
ON TestPartition_PartitionScheme (ID);
GO
--- Step 6 : Insert Data in Partitioned Table
INSERT INTO TestTable (ID, Date) -- Inserted in Partition 1
VALUES (1,GETDATE());
INSERT INTO TestTable (ID, Date) -- Inserted in Partition 2
VALUES (11,GETDATE());
INSERT INTO TestTable (ID, Date) -- Inserted in Partition 2
VALUES (123,GETDATE());
INSERT INTO TestTable (ID, Date) -- Inserted in Partition 2
VALUES (-1,GETDATE());
GO
SELECT *
FROM TestTable;
GO
-- drop table [staging_TestTable_20120704-162405]
SELECT *
FROM [staging_TestTable_20120704-162405];
GO
SELECT *
FROM sys.partitions
WHERE OBJECT_NAME(OBJECT_ID)='TestTable';
GO
select GETUTCDATE ()
-- drop table [TestTableArchive]
CREATE TABLE [TestTableArchive]
(ID INT NOT NULL,
Date DATETIME)
ON TestPartition_PartitionScheme (ID);
GO
CREATE UNIQUE CLUSTERED INDEX IX_TestTable
ON [TestTableArchive](ID)
ON TestPartition_PartitionScheme (ID);
GO
ALTER TABLE [TestTable]
SWITCH PARTITION 1
TO [TestTableArchive] PARTITION 1;
select * from [TestTableArchive]
select * from [TestTable]
SELECT name
FROM sys.databases
WHERE name = N'TestPartition')
DROP DATABASE TestPartition;
GO
CREATE DATABASE TestPartition
ON PRIMARY
(NAME='TestPartition_Part1', FILENAME= 'D:\Partition test\primary\TestPartitionPrimary.mdf', SIZE=2, MAXSIZE=100, FILEGROWTH=1 ),
FILEGROUP TestPartition_Part2
(NAME = 'TestPartition_Part2', FILENAME = 'D:\Partition test\Secondary\TestPartitionSecondary.ndf', SIZE = 2, MAXSIZE=100, FILEGROWTH=1 );
GO
use TestPartition
go
--DROP TABLE TestTable
GO
DROP PARTITION SCHEME TestPartition_PartitionScheme
GO
DROP PARTITION FUNCTION TestPartition_PartitionRange
GO
CREATE PARTITION FUNCTION TestPartition_PartitionRange (INT)
AS RANGE LEFT FOR
VALUES (10);
GO
CREATE PARTITION SCHEME TestPartition_PartitionScheme
AS PARTITION TestPartition_PartitionRange
TO ([PRIMARY], TestPartition_Part2);
GO
-- drop table TestTable
CREATE TABLE TestTable
(ID INT NOT NULL,
Date DATETIME)
ON TestPartition_PartitionScheme (ID);
GO
CREATE UNIQUE CLUSTERED INDEX IX_TestTable
ON TestTable(ID)
ON TestPartition_PartitionScheme (ID);
GO
--- Step 6 : Insert Data in Partitioned Table
INSERT INTO TestTable (ID, Date) -- Inserted in Partition 1
VALUES (1,GETDATE());
INSERT INTO TestTable (ID, Date) -- Inserted in Partition 2
VALUES (11,GETDATE());
INSERT INTO TestTable (ID, Date) -- Inserted in Partition 2
VALUES (123,GETDATE());
INSERT INTO TestTable (ID, Date) -- Inserted in Partition 2
VALUES (-1,GETDATE());
GO
SELECT *
FROM TestTable;
GO
-- drop table [staging_TestTable_20120704-162405]
SELECT *
FROM [staging_TestTable_20120704-162405];
GO
SELECT *
FROM sys.partitions
WHERE OBJECT_NAME(OBJECT_ID)='TestTable';
GO
select GETUTCDATE ()
-- drop table [TestTableArchive]
CREATE TABLE [TestTableArchive]
(ID INT NOT NULL,
Date DATETIME)
ON TestPartition_PartitionScheme (ID);
GO
CREATE UNIQUE CLUSTERED INDEX IX_TestTable
ON [TestTableArchive](ID)
ON TestPartition_PartitionScheme (ID);
GO
ALTER TABLE [TestTable]
SWITCH PARTITION 1
TO [TestTableArchive] PARTITION 1;
select * from [TestTableArchive]
select * from [TestTable]
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